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9x^2+73x=30
We move all terms to the left:
9x^2+73x-(30)=0
a = 9; b = 73; c = -30;
Δ = b2-4ac
Δ = 732-4·9·(-30)
Δ = 6409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-\sqrt{6409}}{2*9}=\frac{-73-\sqrt{6409}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+\sqrt{6409}}{2*9}=\frac{-73+\sqrt{6409}}{18} $
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